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试题原文 |
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(1)2x2-4x=2x(x-2); (2)a2b2-a2c2, =a2(b2-c2), =a2(b+c)(b-c); (3)8a3b2-12ab3c+6a3b2c, =2ab2(4a2-6bc+3a2c); (4)8a(x-a)+4b(a-x)-6c(x-a), =8a(x-a)-4b(x-a)-6c(x-a), =2(x-a)(4a-2b-3c); (5)-x5y3+x3y5, =x3y3(-x2+y2), =x3y3(x+y)(-x+y); (6)(a+b)2-9(a-b)2, =[(a+b)+3(a-b)][(a+b)-3(a-b)], =(a+b+3a-3b)(a+b-3a+3b), =(4a-2b)(4b-2a), =4(2a-b)(2b-a); (7)-8ax2+16axy-8ay2, =-8a(x2-2xy+y2), =-8a(x-y)2; (8)5m(x-y)2+10n(y-x)3, =5(x-y)2[m-2n(x-y)], =5(x-y)2(m-2nx+2ny); (9)(a2+1)2-4a2, =(a2+1+2a)(a2+1-2a), =(a+1)2(a-1)2; (10)m2+2n-mn-2m, =(m2-mn)+(2n-2m), =m(m-n)+2(n-m), =(m-n)(m-2); (11)(a2-4a+4)-c2, =(a-2)2-c2, =(a-2+c)(a-2-c); (12)x2+6x-27=(x-3)(x+9); (13)9+6(a+b)+(a+b)2, =32+2×3(a+b)+(a+b)2, =(a+b+3)2; (14)(x+3y)2+(2x+6y)(3y-4x)+(4x-3y)2, =(x+3y)2-2(x+3y)(4x-3y)+(4x-3y)2, =(x+3y-4x+3y)2, =(-3x+6y)2, =9(x-2y)2. |
经过对同学们试题原文答题和答案批改分析后,可以看出该题目“把下列各式因式分解(1)2x2-4x(2)a2b2-a2c2(3)8a3b2-12ab3c+6a3b2..”的主要目的是检查您对于考点“初中因式分解”相关知识的理解。有关该知识点的概要说明可查看:“初中因式分解”。